Question

Brandon found that a solution of x = 1 was extraneous for his function. What would be a possible denominator in Brandon's function?

2x + 4
x2 + 3x + 9
3x − 11
x2 + 3x − 4

Answer 1

@welshfella

Answer 2

x=1 must be a root of the denominator.
Since the denominator cannot be zero, it is undefined at this point.
Answer: x2+3x-4=1+3-4=0 is the equation that youre looking for

Answer 3

thank you

Answer 4

Your welcome