Question

How can i solve linear equations in one variable?

Answer 1

These types of equations?\[\large\rm 4x+3=2x-1\]

Answer 2

yes

Answer 3

Do you remember the PEMDAS acronym? :)

It tells you how to prioritize these different operations when trying to simplify something like this:\[\large\rm 5+6(2-1)\div2\]You prioritize brackets highest, doing the 2-1 first.\[\large\rm 5+6(1)\div2\]Then multiplying the 6 and 1,\[\large\rm 5+6(1)\div2\]Then division,\[\large\rm 5+3\]and finally adding,\[\large\rm 8\]

You might wonder how that applies to algebraic equations involving one variable.
Well, it turns out that `usually`, when you're trying to solve for some unknown,
you would like to perform these steps in reverse.
That is usually the most straight forward approach.

Answer 4

ooh

Answer 5

Lemme set up a more straight forward example actually,\[\large\rm 4x-3=9\]The idea is, in order to get x alone, solving for it,
you need to "undo" a bunch of operations.

So in this example, notice that the x is being `multiplied by 4` and `subtracted by 3`.
We want to think of this PEMDAS idea but in reverse,
we would like "undo" the most simple steps first.

So to undo subtraction, we use addition.
We'll start by adding 3 to each side of the equation.
(By making the same change to each side, the equation stays true and balanced).\[\large\rm 4x-3+3=9+3\]The subtraction and addition undo one another on the left side of the equation,\[\large\rm 4x=9+3\]

Answer 6

I know I'm rambling on a bit here :) lol
but it's a fun question

Answer 7

im confuse because the question

Answer 8

the question? :o

Answer 9

ya this is for my school work and i do not understand at all.the way she wrote the question

Answer 10

She gave you this question:
`How can i solve linear equations in one variable?`
and wants you to explain?

Answer 11

yes

Answer 12

also


KEEP IT ___________________.
The goal is to figure out how much each x weight weighs. You do this by getting one x on one side and its value on the other side.
STEPS TO SOLVING AN EQUATION
1. Simplify each side of the __________________.
2. Get the __________________ on one side of the ___________________.
3. Get the _____________ by ___________________. (Solve for the variable)
4. ___________ your solution.
Follow along on page 3, Example 1. E2(x + 1) = 5x + 4 E x

Simplify each side of the equation.

Answer 13

1. Simplify each side of the `equation`.
Example: (Not using your example cause I'm not sure what the E's are about)\[\large\rm 2(x+3)=5x+1\]Simplifying the left side gives us,\[\large\rm 2x+6=5x+1\]

Answer 14

2. Get the `variable` on one side of the `equation`.
We would like all of the x's on one side of the equation.
It's usually better to move the smaller x's around.
So in this example, I'll subtract 2x,\[\large\rm 6=5x+1-2x\]\[\large\rm 6=3x+1\]

Answer 15

3. Get the `solution` by `applying Algebra`.

I'm not really sure what she wants for this step, maybe something like that.
You get the solution by applying steps.

Answer 16

4. `Verify` your solution.

After you have found your x value,
you want to plug that value back into the original expression and make sure that it holds true.

Answer 17

I think there is some popular expression that teachers use which is
KISS = keep it simple, stupid

I'm not sure where it comes from, but it sounds familiar :\

Answer 18

lol are in the usa

Answer 19

yes :U

Answer 20

ooh i thought you where not because its late lol

Answer 21

:)