Question

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Answer 1

find in the form \[f(x)=ax^2+bx+c\]
the equation of the quadratic whose graph cuts the x-axis at 3, passes through (5,12), and has the axis of symmetry x=2

Answer 2

The axis of symmetry formula:

x = -b/2a

-b/2a = 2

The quadratic cuts the x - axis at 3

the point (3,0 ) is on the graph

and you have (5,12)

both of the points satisfy the equation

You have 3 equations.