suppose certain coins have weights that are normally distributed with a mean of 5.767 g and a standard deviation of 0.076 g. A vending machine is configured to accept those coins with weights between 5.677 g. and 5.857 g

a. If 290 different coins are inserted into the vending machine, what is the expected number of rejected coins? (round to the nearest integer)

Question

suppose certain coins have weights that are normally distributed with a mean of 5.767 g and a standard deviation of 0.076 g. A vending machine is configured to accept those coins with weights between 5.677 g. and 5.857 g

a. If 290 different coins are inserted into the vending machine, what is the expected number of rejected coins? (round to the nearest integer)

mathmale · Answer

Big picture:  You'll first need to find the area under the normal cur e between 5.677 and 5.857 grams.  Are you able to do that?

anonymous · Answer

no

mathmale · Answer

Have you used a table of z-scores before?

anonymous · Answer

yes

mathmale · Answer

Good.  Find the z-score corresponding to 5.857 grams when the mean is 5.757 and the std. dev. is 0.076 grams

mathmale · Answer

the proper formula to use is the following:|dw:1449937049116:dw|