What are the approximate solutions of
2x^2 + x = 14 rounded to the nearest hundredth?
a. x ≈ -2.41 and x ≈ 2.91
b. x ≈ -2.91 and x ≈ 2.41
c. x ≈ -5.82 and x ≈ 4.82
d. No real solutions

Question

What are the approximate solutions of 
2x^2 + x = 14 rounded to the nearest hundredth? 
a. x ≈ -2.41 and x ≈ 2.91
b. x ≈ -2.91 and x ≈ 2.41
c. x ≈ -5.82 and x ≈ 4.82
d. No real solutions

welshfella · Answer

2x^2 +x - 14 =  0
to solve use the quadratic formula

x = [-b +/- sqrt(b^2-4ac)] / 2a

where the equatuion is  of the form

ax^2 + bx + c = 0

welshfella · Answer

so here a = 2, b = 1 and c = -14

plug these values into the formula

welshfella · Answer

the +/-  means there are 2 values for x as follows
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