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Physics 6 Online
OpenStudy (anonymous):

If you throw a ball at 35° and 10.0 m per s, what is the horizontal component of velocity? 8.2 m per s 10 m per s 0.0 m per s 5.7 m per s I pick A. >-< Although I'm not very confident in physics.

OpenStudy (shamim):

Horizontal component of given velocity=Vx=V*cos theta=10*cos35=?

OpenStudy (shamim):

Plz use calculator

OpenStudy (anonymous):

@shamim So you're saying A is incorrect?

OpenStudy (shamim):

No i m not telling so

OpenStudy (shamim):

I hv no calculator now

OpenStudy (shamim):

Wt answer did u get frm my calculation

OpenStudy (anonymous):

It's 10cos(35) right? @shamim

OpenStudy (shamim):

Yes!

OpenStudy (anonymous):

Ah okay, I was right! Thank you!! @shamim

OpenStudy (shamim):

U r most welcome!!!

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