Question

If you throw a ball at 35° and 10.0 m per s, what is the horizontal component of velocity?
8.2 m per s
10 m per s
0.0 m per s
5.7 m per s
I pick A. >-< Although I'm not very confident in physics.

Answer 1

Horizontal component of given velocity=Vx=V*cos theta=10*cos35=?

Answer 2

Plz use calculator

Answer 3

@shamim So you're saying A is incorrect?

Answer 4

No i m not telling so

Answer 5

I hv no calculator now

Answer 6

Wt answer did u get frm my calculation

Answer 7

It's 10cos(35)
right? @shamim

Answer 8

Yes!

Answer 9

Ah okay, I was right! Thank you!! @shamim

Answer 10

U r most welcome!!!