Question

what is the integration of
1/1-2.v^2 dv ??

Answer 1

\(\int {1 \over 1-2v^2} dv \) ??

if so

\( {1 \over 1-2v^2} = {1 \over (1-\sqrt{2}v)(1+\sqrt{2}v)}\)

then partial fractions and log integrals....