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plz tell me that on why (0+sin3t) became 3sin3t? and is this correct???
@pooja195
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@AlexandervonHumboldt2
plz help me
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yup i know its derivative and we have to use chain rule but look why they do thz (0+sin3t) came 3sin3t i am not getting thz?
@mayankdevnani
is it correct?
@SolomonZelman
hi
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if \[y=\tan u\] \[\frac{ dy }{ dx }=\sec^2 u*\frac{ du }{ dx }\]
\[(5-\cos 3t)'=0+3\sin 3t\]
okay got it thanks :)
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