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Mathematics 13 Online
OpenStudy (shalayla4):

What is the area of a regular hexagon with a perimeter of 12 and apothem (Square root of) 3 cm? A.) 36cm B.) 6 (square root of) 3 cm C.) (Square root of) 3 cm D.) 12 (Square root of) 3 cm

OpenStudy (tkhunny):

1) Do not post problems with no work shown. 2) Draw one and figure it out.

OpenStudy (alexandervonhumboldt2):

first of all you need to find the side.

OpenStudy (bubblegum.):

The code of conduct does not say that we have to post our work along with the question!

OpenStudy (shalayla4):

Yea^

OpenStudy (bubblegum.):

\(\Huge\ddot\smile\)

OpenStudy (alexandervonhumboldt2):

lets go back to the question

OpenStudy (shalayla4):

Thank you :) Alex

OpenStudy (alexandervonhumboldt2):

first of all we need to find the side

OpenStudy (alexandervonhumboldt2):

hexagon has 6 sides

OpenStudy (shalayla4):

Okay, how do I do that?

OpenStudy (alexandervonhumboldt2):

to find the side we divide the perimeter by the number of sides

OpenStudy (shalayla4):

Oh okay so the side is 2?

OpenStudy (alexandervonhumboldt2):

yes now the formula for the area of hexagon is \[A=\frac{ 3\sqrt3 }{ 2 }*a^2\] where a is a side

OpenStudy (alexandervonhumboldt2):

substitute 2 and solve

OpenStudy (tkhunny):

Just draw one triangular piece and multiply by 6.|dw:1450118443658:dw|

OpenStudy (shalayla4):

Substitute 2 for a ?

OpenStudy (alexandervonhumboldt2):

yeah

OpenStudy (shalayla4):

So my answer would be 6 sqrt (3) ?

OpenStudy (tkhunny):

Did you get the same result using both methods? Use Ale's formula for the whole thing. Use my hint to verify.

OpenStudy (shalayla4):

What formula is that?

OpenStudy (tkhunny):

The one provided by Alex? Where did you get \(6\sqrt{3}\)?

OpenStudy (shalayla4):

I did indeed, I got it by using his method. And it was correct. Thank you so much Alex!!!

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