Question

for intermediate algebra how do I solve the equation. 4/x-3-1=x-1/x-3

Answer 1

Lets work on notation a little.

4/x-3 mean \(\dfrac{4}{x} - 3\)

x-1/x-3 means \(x - \dfrac{1}{x} - 3\)

If you mean otherwise, you will need additional grouping symbols.

4/(x-3) mean \(\dfrac{4}{x-3}\)

(x-1)/(x-3) means \(\dfrac{x - 1}{x - 3}\)

Is that more like what you intended to solve?

Answer 2

x−1x−3