Question

(QUICK) The vertex of this parabola is at (2, -1). When the y-value is 0, the x-value is 5. What is the coefficient of the squared term in the parabola's equation?

Answer 1

ok.. so the general vertex form is

\[y = a(x - h)^2 + k\]

(h, k) is the vertex so input them into the equation

Answer 2

Would you like the Graph also?

Answer 3

next to find the value of a, substitute the point (5, 0)

and then solve for a

Answer 4

and the answer would be

Answer 5

You should try to solve it.