Question

MEDAL!!!


Solve the expression...

Answer 1

What expression?

Answer 2

\[\large \frac{ 2k }{ 4k - 4 } - \frac{ 2k }{ k-1 }\]

Answer 3

I got:
\[\large \frac{ 3k(-k + 1) }{ 2(k-1)^2 }\]

Answer 4

\( \dfrac{ 2k }{ 4k - 4 } - \dfrac{ 2k }{ k-1 }\)

\( \dfrac{ 2k }{ 4(k - 1) } - \dfrac{ 2k }{ k-1 }\)

\( \dfrac{1}{4}\left(\dfrac{ 2k }{ k -1 } \right) -1\left(\dfrac{ 2k }{ k -1 } \right) \)

Answer 5

\( \left(\dfrac{1}{4}-1\right)\left(\dfrac{ 2k }{ k -1 } \right) \)

Answer 6

\( \left(\dfrac{-3}{4}\right)\left(\dfrac{ 2k }{ k -1 } \right) \)

Answer 7

\( \dfrac{ -6k }{ 4k -4 } \)

Answer 8

simpler, no?

Answer 9

Yes but is my answer correct?

Answer 10

yes

Answer 11

thank you!

Answer 12

and both our answers simplify to

\( \dfrac{ -3k }{ 2k -2 } \)