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Find y' and simplify y=3x^-2+2x^3+5
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U know y'=dy/dx Right?
Differentiation of y with respect to x
Do u know dx^4/dx=4*x^3
dx^-3/dx=-3*x-4
One more thing is d(4)/dx=0
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Because differentiation of any constant is equal 0
\[y=3x^{-2}+2x^3+5\] \[y'=(3x^{-2})'+(2x^3)'+(5)'\] use \((ax^n)'=anx^{n-1}\)
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