Can someone pleeeeeeaaaaseeee check my work???? I'm begging and I can't fail

Question

anonymous · Answer

sure

anonymous · Answer

help me though please

anonymous · Answer

Here is a better picture

anonymous · Answer

FLVS?

anonymous · Answer

Yes

anonymous · Answer

I do the same what teacher do you have?

anonymous · Answer

hey math male please help me

anonymous · Answer

What is the product of three square root of eight times four square root of three? Simplify your answer.

mathmale · Answer

Sorry to pour cold water on your chat, but I ask you to stick to the (math) topic here.

anonymous · Answer

What is the product of three square root of eight times four square root of three? Simplify your answer.

anonymous · Answer

Have u tried using mathway?

mathmale · Answer

Hannah, please open a new post.  Your question has nothing to do with Nicole2525's post.

anonymous · Answer

no

anonymous · Answer

and my name is not hannah its lisa

mathmale · Answer

Keep your focus on MATH, please.

anonymous · Answer

Can u help check my work? Mathmale

mathmale · Answer

I'd have to see your work to do that.

anonymous · Answer

Ok well the only thing I think I need help on is finding the slope because I don't know what to do

mathmale · Answer

You're given a table of data points.  Have you graphed them yet?

anonymous · Answer

No how would I do that?

mathmale · Answer

|dw:1450457656063:dw|

mathmale · Answer

choose appropriate scale divisions for both axes, based on the data given you.

anonymous · Answer

It won't let me click on that:( I'm on a tablet

mathmale · Answer

Note that "time" varies from 10 minutes to 40 minutes, and that distance varies from 4 to 15 miles.

Sorry you apparently can't see my illustration on your tablet.  But there's not much I can do about that.  Could you find a computer?

anonymous · Answer

I'm sorry the only one is my dads but he is using it right now:(

mathmale · Answer

the whole point here is to determine whether or not those points appear to lie on a straight line.  The more this straight line describes the points, the higher the correlation.

You could graph the points on paper and describe to me what you see.
\Or you could continue this discussion later, when your dad is off his computer.

anonymous · Answer

I will see if I can get on his computer later:) Thankyou for trying to help though, I appreciate it

rhondasommer · Answer

I was always tught that slope is rise over run. So, if you plot two point on a graph $$ex) (0,1) (1,1)$$ 
you locate rise(going up)  divided by run (going over) which could o you a large fraction which you would then simplify.