Chuck-A-Luck: To win any money, at least two of your dice must show the same number. What's the likelihood of winning anything after one roll? Explain your answer.
you have 6 dice right?
okay well, if you had 6 dice and you need 2 of the same thats under half so itd be 1/3 then you turn that into a percentage, i think
Here is the description of the game that was told to me: This is a simple game that involves a single roll of three dice. The bet is that a single value will appear on at least one of the dice in that roll. If your number appears once, you win one times your bet. If the number appears on two dice, you win twice your bet, and if the number appears three times, you win three times the bet. If the number doesn't appear on any of the dice you lose the bet.
okay so, since theres 6 numbers on each dice and three dice youd have a fraction of 3/18 which is 1/6 simplified.
Ohh, okay, I see. So, you are saying that there is a 16.7% chance of winning after one roll?
hold on im checking with my friend real quick
Okay
yeah i believe youre right
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