Question

Solve for x.
7 + 6(x + 2) = 43

A. x = 4
B. x = 5
C. x = 3
D. x = 8

Answer 1

@pooja195

Answer 2

@satellite73

Answer 3

@mathmale

Answer 4

O hai photon

Answer 5

I know and don't know.

Answer 6

\[A(B+C) = A*b + A*C\]

Answer 7

How is that? there is only on A

Answer 8

we need to take care of that 6(x+2) first

6x+12+7 = 43

Answer 9

1) subtract 7
b) divide by 6
iii) subtract 2

Answer 10

those three steps will get your answer

Answer 11

What am I distributing or something?

Answer 12

7+6(x+2) = 43

6(x+2) = 6x+12 we're distribution the 6 in the ( )

Answer 13

I saw that. How would I do it his way? :P

Answer 14

XD

Answer 15

let me show you

7+6(x+2) = 43
-7 -7
step #1 subtract 7

6(x+2) = 36
6 6
step #2 divide by 6

x+2 = 6

step #3 subtract 2

x+2 = 6
-2 -2

x= 4

Answer 16

the way I showed you

7+6(x+2) = 43

7+6x+12 = 43

6x+19 = 43
-19 -19

6x = 24
6 6

x = 4

Answer 17

ohhh

Answer 18

I can remember his way XD

Answer 19

you see the deal here right? two different ways of approaching the same problem and same answer.

Answer 20

true

Answer 21

His way of doing it though is a little easier whatever works for you

Answer 22

@AnimeWover you you understand or do you want more help?

Answer 23

I understand

Answer 24

Alright. Just makin sure.

Answer 25

XD

Answer 26

Here's an alternative approach: Subtract 7 from both sides of the given equation:

7 + 6(x + 2) = 43

Then divide the result by 6.

Then what?

Answer 27

um. That was just stated