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f(x)=4x^3 and g(x)=2x. What is f(x)/g(x)? A) 4x B) 2x^2 C) 2x^3 D) 8x^4
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put \(f\) over \(g\) and then cancel some stuff
\[f(x)=4x^3~and~g(x)=2x\]substitute it into\[\frac{ f(x) }{ g(x) }\]\[\frac{ f(x) }{ g(x) }=\frac{ 4x^3 }{ 2x }\]simplify it
we noticed that 4x^3 and 2x can be divide by 2x
\[=\frac{ 2x^2\times2x }{ 1\times2x }\]
\[=\frac{ 2x^2\times\cancel{2x} }{ 1\times\cancel{2x} }\]
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\[=?\]solve it @kaioken360
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