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\[\sin^5xcos^2x=(\cos^2x-2\cos^4x+\cos^6x)sinx\]
I can't see if you get your answer in here https://answers.yahoo.com/question/index?qid=20090114200557AA97oTu
\[\sin x*\sin^4x=\sin^5x\] \[\sin^4x=\sin^2x*\sin^2x=(1-\cos^2x)(1-\cos^2x)=(1-2\cos^2x+\cos^4x)\] \[(1-2\cos^2x+\cos^4x)(\cos^2x)=\cos^2x-2\cos^4x+\cos^6x\]
got it thanks man
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