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One who and one what cost 12 dollars. One who and one where cost 11 dollars. One what and one where cost ten dollars. How many dollars do 2 who’s cost?
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who=x what=y where=a x+y=12 x+a=11 y+a=10 add the first 2 together so it is 2 who's and a what and a where subtract the last equation so it only leaves 2 who's :)
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