Alicia estimated her test score to be 85. Her actual score was 80.

What was the percent error in Alicia’s estimate? Round your answer to the nearest tenth of a percent.

Question

Alicia estimated her test score to be 85. Her actual score was 80.
 
What was the percent error in Alicia’s estimate? Round your answer to the nearest tenth of a percent.

anonymous · Answer

@Michele_Laino @MissNoName @mathmath333 @Mehek14 @Abhisar @AlexandervonHumboldt2

anonymous · Answer

6

anonymous · Answer

6%

anonymous · Answer

5.9%

michele_laino · Answer

the requested error, is given by the subsequent computation:
$$\huge  \frac{{85 - 80}}{{85}} \times 100 = ...?$$

solomonzelman · Answer

$\color{#000000 }{ \displaystyle \frac{ \rm |correct-estimated| }{\rm correct}\times 100  }$

solomonzelman · Answer

Isn't that the case?

anonymous · Answer

5.8

solomonzelman · Answer

We are searching for how much wrong was the estimated score from the actual score... (not the other way around)

I might be wrong, but I think we are dividing by 80.

michele_laino · Answer

It is $5.88 \%$ so, that's right!

anonymous · Answer

k

michele_laino · Answer

which can be rounded to $6 \%$

anonymous · Answer

Round your answer to the nearest tenth of a percent.

anonymous · Answer

5.7

michele_laino · Answer

sorry, it can be rounded to $5.9 \%$

anonymous · Answer

yeah i  made a mistake

solomonzelman · Answer

are you sure we are dividing by 85, not 80?

solomonzelman · Answer

I'm not very certain about this, that's why I'm asking.