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Mathematics 19 Online
OpenStudy (anonymous):

The horizontal asymptotes of the function f(x)= sqrt 4x^2+x/2x-1

OpenStudy (campbell_st):

well there isn't a horizontal asymptote, it is actually an oblique asymptote to find it, simply do some polynomial or synthetic division. |dw:1450742367282:dw| the quotient of the division will be the oblique asymptote hope it helps

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