Question

No 5 please. calculus 3

Answer 1

@Loser66 Help with no 5 please. just wanna double check and make sure I am doing the right thing.

Thank you..

Answer 2

Where is the question?

Answer 3

@Lovelarap No 5 please. thank you

Answer 4

Thank you.

Answer 5

I got dz/dt=-3(df/dx)+2(df/dy)

Answer 6

Sorry, I can't really help you because i'm still on pre-calc.

Answer 7

Oh Ok, No problem lets wait for @Loser66 .

Answer 8

@Astrophysics @ShadowLegendX No 5 please.

Answer 9

show your work first

Answer 10

Ok \[x=2-3t \] \[y=3+2t\]

\[dx/dt= -3\]

\[dy/dt=2\]

Therefore \[dz/dt=(df/dx)(dx/dt)+(df/dy)(dy/dt)\]

\[dz/dt=-3(df/dx)+2(df/dy)\]

Answer 11

@Loser66 .