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Choose one of the factors of x15 − 64. x5 − 4 x10 − 4x5 + 16 x10 − 4 x15 + 8x + 16
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\(\color{#000000 }{ \displaystyle x^{15}-64 }\) ?
\(\color{#000000 }{ \displaystyle (x^{5})^3-4^3 }\)
\(\color{#000000 }{ \displaystyle b^3-a^3=(b-a)(b^2+ba+a^2) }\) (this is the rule)
I am thinking A from the info you have given so far.
Yes, that was quick:)
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is this question "for all that applies" ?
I just want to say, by asking this question, that there is another correct answer.
I got a 100%, thank you again!
There is no other correct choice. A was the only one.
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