Question

if x=cosh theta, y=sinh theta, obtain dy/dx in parameter theta. then sketch graph of y and dy/dx regarded as function theta

Answer 1

\[\dfrac{d (\sinh \theta)}{d (\cosh \theta)}= \dfrac{y'_\theta}{x'_\theta} = \coth \theta\]
and then play with \( csch ^{2} x= \coth^{2} x - 1\)

Answer 2

Nice

Answer 3

the identity is use to obtain what actually?

Answer 4

you wanna flip it back into x and y, i think

Answer 5

i see, thank you for your help :)

Answer 6

mp