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Will Medal and Fan, please help? Trig Question: Need to find two vertical asymptotes for f(x) = - tan 4x? I heard that you need to find values when cos(x)=0, but I don't know how to find x...
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@sweetburger can you help please?
Do you know the unit circle?
hint: the period of the function \(x \rightarrow -\tan x\) is \(T_0=\pi\), and its vertical asymptotes are located at \(x= \pm \pi/2, \pm 3\pi/2,...\) Now the period of the function \(x \rightarrow -\tan (4x)\) is \(T_1=T_0/4\), so every value of \(x\) at which there is an asymptote for the function \(x \rightarrow -\tan x\) is reduced by a factor \(4\)
Refer to the attached plot.
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