Mathematics
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OpenStudy (anonymous):
help?
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OpenStudy (anonymous):
@Directrix
OpenStudy (dayakar):
t1=100, t2=105,t3=110,t4 =115
can u find common difference (d) = t2-t1
OpenStudy (anonymous):
the common difference is 5
OpenStudy (dayakar):
good
first term = t1 =a =
tn = a+(n-1)d
find it
OpenStudy (dayakar):
r u doing
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OpenStudy (anonymous):
should i solve for t?
OpenStudy (dayakar):
yes ,substitute a and d in tn
OpenStudy (anonymous):
t= a/n+d-d/n
OpenStudy (dayakar):
a=100,d=5 from the problem
tn = a+(n-1)d [ replace a with 100 and d with 5 and simplify]
OpenStudy (dayakar):
tn = 100+(n-1)5 [simplify it]
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OpenStudy (dayakar):
what it related about?
OpenStudy (anonymous):
huh?
OpenStudy (dayakar):
n th term in A.P is tn =a+(n-1)d
= 100+(n-1)5
= 100+5n- 5
= ?
OpenStudy (anonymous):
= 5n+95
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OpenStudy (dayakar):
very good ,this is first question answer
OpenStudy (anonymous):
ok ty
OpenStudy (dayakar):
t1=1,t2= -5, t3= 25, t4 = -125 are i G.P
first term = t1 =a = 1
common ratio (r) = t2/t1
can u find it r
OpenStudy (dayakar):
n th term in G.P = tn = a*r^n-1
OpenStudy (anonymous):
-5^n-1
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OpenStudy (anonymous):
1*5^n-1
OpenStudy (anonymous):
would the answer be C?
OpenStudy (dayakar):
tn =1* (- 5)^n-1
tn = 1 . (-5)^n-1
OpenStudy (dayakar):
is it clear
OpenStudy (anonymous):
yes