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Mathematics 23 Online
OpenStudy (anonymous):

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OpenStudy (dayakar):

any GP is in the form of a,ar,ar^2, ar^3 ....... here t1=a t2= ar t3= ar^2 t4= ar^3

OpenStudy (dayakar):

observe each term can u find tn

OpenStudy (dayakar):

here common ratio (r) = t2/t1= t3/t2=t4/t3

OpenStudy (dayakar):

2,4,8,16 compare and write a and r

OpenStudy (anonymous):

the common ratio is 2

OpenStudy (mathmale):

Right. Now that you have the common ratio, r, such that r=2, which of the four listed formulas would be the correct one for the given geometric sequence?

OpenStudy (dayakar):

compare in number in t LHS , and power of r in RHS u can easily write n th term = tn =

OpenStudy (dayakar):

a=2. r= 2 substitute these values in tn =a*r^n-1

OpenStudy (dayakar):

Question 7 just replace n with 9 t9 =

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