Question

Calculus NO 5 and 6 please.

Answer 1

@mathmale

Answer 2

Anybody?

Answer 3

@xapproachesinfinity

Answer 4

Don't post without showing your work. Give it a go.

Answer 5

\[z(2-3t, 3+2t)\]

\[z(x,y)\]

Where \[x=2-3t\]
and
\[y=3+2t\]



so \[dz/dt= (df/dx)(dx/dt)+(df/dy)(dy/dt)\]

where \[dx/dt=-3 \]

and \[dy/dt=2\]

hence \[dz/dt=-3(df/dx)+2(df/dy)\]