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2. in the figure below,PT=2x,TR=y+4,QT =X+2, and TS=y find the values of x and y in parallelogram PQRS a) x=2,y=4 b) x=0,y=2 c) x=6,y=8 d) x=4,y=6
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well you need to know the diagonals of a parallelogram bisect each other. So using this property PT = TR and QT = TS that means 2x = y + 4 Equation 1 x + 2 = y Equation 2 by substituting equation 2 into equation 1, you get 2x = x + 2 + 4 or 2x = x + 6 now you can solve for x. When you get a value substitute it inot equation 2 to find y. Hope it helps
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