What is the equation of the quadratic graph with a focus of (3, 6) and a directrix of y = 4?

f(x) = one fourth (x − 3)2 + 1
f(x) = one fourth (x − 3)2 + 5
f(x) = −one fourth (x − 2)2 + 5
f(x) = −one fourth (x − 2)2

Question

What is the equation of the quadratic graph with a focus of (3, 6) and a directrix of y = 4?

 f(x) = one fourth (x − 3)2 + 1
 f(x) = one fourth (x − 3)2 + 5
 f(x) = −one fourth (x − 2)2 + 5
 f(x) = −one fourth (x − 2)2

nnesha · Answer

|dw:1451280127837:dw|
draw given information 
point at (3,6)
directrix at y=4

princesssleelee · Answer

then what

nnesha · Answer

in order to write the equation you have to find 
distance between point and parabola (any point on the parabola)
and distance between directrix and point |dw:1451280373329:dw|