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Mathematics 8 Online
OpenStudy (princesssleelee):

What is the discontinuity and zero of the function f(x) = the quantity of 2 x squared plus 5 x minus 12, all over x plus 4? Discontinuity at (−4, −11), zero at (three halves , 0) Discontinuity at (−4, −11), zero at (negative three halves , 0) Discontinuity at (4, 5), zero at ( three halves , 0) Discontinuity at (4, 5), zero at (negative three halves , 0)

OpenStudy (princesssleelee):

@Mehek14

OpenStudy (princesssleelee):

@pooja195

OpenStudy (aihberkhan):

Okay. So first we just want to put our numbers together and make an equation. So we would solve this: \[f(x) = \frac{ (x + 4) (2x - 3) }{ ( x + 4) }\] Due to this. It looks as if the first one is the correct answer.

OpenStudy (aihberkhan):

Hope this helped! Have a great day! :) If you see that I am online and need help with a question, just tag me in your question! @princesssleelee

OpenStudy (princesssleelee):

Thank you! that is what i got as well :) i do have 2 more questions that i need assistance with :) if youre able to help, that would be amazing! @AihberKhan

OpenStudy (princesssleelee):

Which graph represents the function of f(x) = the quantity of 9 x squared plus 9 x minus 18, all over 3 x plus 6? graph of 3 x plus 6, with discontinuity at 2, 12 graph of 3 x plus 6, with discontinuity at negative 2, 0 graph of 3 x minus 3, with discontinuity at negative 2, negative 9 graph of 3 x minus 3, with discontinuity at 2, 3

OpenStudy (aihberkhan):

Yes, I am able to help. However, it is better if you make a separate post for each question! :) Also, I have to see if I am able to help, because I might not understand it :)

OpenStudy (aihberkhan):

Can you make a separate post for each question? :) @princesssleelee

OpenStudy (tkhunny):

@princesssleelee This is no good, "that is what i got as well" SHOW us what you got. Don't make other people do the work when you've already done it!

OpenStudy (princesssleelee):

@tkhunny i was unsure of my answer, and it was done with a calculator, so i was just making sure, sorry. but yes i can make a separate posy @AihberKhan

OpenStudy (tkhunny):

You did not answer my objection. Show YOUR work - every time. No excuses.

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