Question

3. Simplify the radical expression.

Sqrt 490y^5w^6

A. 245y^2w^3
B. 7y^2w^3 sqrt 10y
C. 7y^2w^3 sqrt 10yw
D. 7 sqrt 10y^5w^6

Answer 1

for the first step you can rewriting it like

sqrt(49*10*y^4*y*w^2*w^2*w^2) = ?

yes ?

Answer 2

so you know that 49=7^2
than what are pefect squares you can take them out from squaroot - yes ?

Answer 3

No! I'm sorry

Answer 4

I just don't understand this stuff!