hello
HELLO THIS IS CONSIDERED SPAM ONLY POST QUESTIONS OR THANKS
what is the solution to the system of equations? Use the linear combination method (with or without multiplication) 4x - 5y =-18 3x + 2y = -2 (a) (-2,7) (b) (3,-1) (c) (-1,3) (d) (-2,2) help.
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\(\color{#000000 }{ \displaystyle 4x-5y=-18 }\) \(\color{#000000 }{ \displaystyle 3x+2y=-2 }\) One way to do it is through "elimination". I will multiply \(\sf eq\text{#}1\) times 3, and \(\sf eq\text{#}1\) times -4 \(\color{#000000 }{ \displaystyle (4x-5y=-18)\times 3 }\) \(\color{#000000 }{ \displaystyle (3x+2y=-2)\times (-4) }\) I get, \(\color{#000000 }{ \displaystyle 12x-15y=-54 }\) \(\color{#000000 }{ \displaystyle -12x-8y=8 }\)
Then, add the equations
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