Question

Two construction companies are building 1,100 feet tall skyscrapers. Company A has finished 550 feet of construction in 5 1/2 months. Company B has finished 385 feet of construction in 3 1/2 months. If both companies continue to build at the same rate, which company will reach the top first? Pls help me😁😁😁😁

Answer 1

do you have same idea ?

Answer 2

for how begin this calculi ?

Answer 3

Can you explain how to solve this problem and an explanation

Answer 4

first you need calculi for company A and B in how many day building 1 feet
can you calculi it here now ?

Answer 5

5 1/2 months = ? days

Answer 6

31 times 5 1/2
Right?????

Answer 7

Or 30 times 5 1/2

Answer 8

suppose yes than you get one month has 30 or 31 days - depend how you calculi

Answer 9

Ok thanks I think I got it

Answer 10

ok. but i like check your calculi here - ok. ?

Answer 11

and again than you see this 550 feet is a half part of this needed building feet ,yes ?

Answer 12

so this mean that than you duble this period of 5 1/2 month you get the necessary tome for company A to building these 1100 feet - yes ?

Answer 13

sorry - the necessary time ...

Answer 14

ok. so than doubling this period of company A you get 1100 feet ended in 11 month
- yes ?

Answer 15

so for company B you know that build 385 feet in 3 1/2 month so
3 1/2 month are 105 days

385 feet in 105 days
1100 feet --- x days
---------------------- cross multiplie and calculi x

x = 1100*105/385 = 300 days
- this mean that company B build these 1100 feet in 300 days

Answer 16

for company A this 11 month mean 11*30=330 days so from this result that company B will reach the top first

ok ?

hope you understand it sure

yes ?

Answer 17

This problem invovles rates of change: one constant rate for one company and another, different, constant rate for the other company. We assume that at the beginning of construction, the height of the building is 0, and at the end the height is 1,100 feet.

An appropriate model for this construction would be a linear function with zero initial value (height of building is 0 ft. and time t=0).

Building 1: \[h _{A}(t)=\frac{550ft }{ 5.5 mo }*t _{A}=1100ft\]

Answer 18

Constructing a similar equation for Building B:\[h _{B}(t)=\frac{385ft }{ 3.5 mo }*t _{B}=1100ft\]

Answer 19

Solve each of these two equations for the time required to complete all 1100 feet of construction. The contractor with the shorter construction time "wins."

Answer 20

Note how these equations follow the pattern

Amount = (rate)*(time).

Also note that you could solve both equations for time before inserting numeric values:

time = (amount) / (rate)

Answer 21

Note that there's no need to convert "months" to "days."