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Mathematics 19 Online
OpenStudy (anonymous):

Please help!! Will fan and medal!!!!! Question attached in comments

OpenStudy (anonymous):

OpenStudy (boldjon):

it's um

OpenStudy (anonymous):

3252 was it.

OpenStudy (anonymous):

Calculate for the value of "k" first (constant) using the ffg given: A= 2000 P= 2400 t=6 hrs

OpenStudy (anonymous):

then after that solve for P again when t= 16 hrs. let's see P/A = e^kt 2400/200=e^{6k} ln of both sides 0.18232 = 6k k = 0.0304 solve for t= 16 P = (2000)(e^(0.0304x 16) =3252.22 :)

OpenStudy (anonymous):

Thank you :)

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