What are the real or imaginary solutions of the polynomial equation? x^4 - 52x^2 + 576 = 0 A. 4, -4 B. 4, -6 C. 4, -4, 6, -6 D. No solution Fan and medal will be given out to whoever is most helpful. Thank you in advance!!! :D
compare with ax^2+bx+c=0
this is a bi-quadratic equation, and in order to solve it, it is necessary to make this variable change: \(x^2=z\), so we get: \(z^2-52z+576=0\) so, please solve such equation for \(z\)
or use 52=36+16 and 36*16=576
Thank you guys! :) this was helpful.
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Let's go
If Y=x² substitute Y into X² Y²-52Y+576=0
Now picking from Mohd.Amir clue Y²–16Y–36Y+576=0
Do u know one thing I hate about maths is the big number but thanks to technology let's move let's move to the next level by finding Y even though we are still seeing it
Oh! Sorry, I'm really busy and got sidetracked. Thank you for all your help :) @Daniel56k
Y(Y–16)–36(Y–16)=0
(Y–16)(Y–36)
The answer is C.
Okay let me just finish the calculation up please
Just kidding u are right
Lol ^.^ thank you
Y=16,Y=36 Substitution √x²=√16 X=4 X=6
Yep
I found the number right
Yeppeeeeeee
Lol ^.^
My head is so hot right now it can burn down a whole house.......bye
Have to cool my head off with so other maths
Some other maths
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