7^16 7^-18
---- = ------
7^12 ?
The missing denominator is?
A.7^(-6)
B.7^(-14)
C.7^(-22)
D.7^22

Question

7^16      7^-18         
---- =  ------
7^12          ?
The missing denominator is?
A.7^(-6)
B.7^(-14)
C.7^(-22)
D.7^22

decarr432 · Answer

Any one have a clue?

hwyl · Answer

laws of exponent involving fractions
$\huge \frac{a^m}{a^n} = a^{m-n} $

decarr432 · Answer

huh?

ikram002p · Answer

do you know cross multiply ?? @Decarr432

decarr432 · Answer

I'm taking a pretest on things iv'e never been taught 
and yes i know cross multiplication

hwyl · Answer

figure out the left hand side of the equation using the laws of exponent first
then the right side of the equation will flow

decarr432 · Answer

Okay one minute please

ikram002p · Answer

know what @hwyl  idea is better :P

hwyl · Answer

do not use a calculator, just use the laws of exponent that I laid out

decarr432 · Answer

So solve the exponents first right?

decarr432 · Answer

or would I just 7^4?

hwyl · Answer

correct

hwyl · Answer

now that we figured the left hand side, let us look at the right hand side

hwyl · Answer

let us just focus on the exponent since we know that all of the base are 7 anyway. 

4 = -18 - (?)