Question

Write y=2x^2+12x+14 in vertex form

Answer 1

the vertex is at

Answer 2

sorry am confused how did u get 1/9

Answer 3

factor 2 out, you get y = 2(x^2 +6x +7)
inside the parenthesis only: x^2 +6x +7 = x^2 +2*x*3 +3^2 -3^2 +7
= (x+3)^2 -2
Now, put 2 in the original in
\(y = 2((x+3)^2 -2) = 2(x+3)^2 -4 \)
Make a comparison with the general form:
\(y = \color{red}{a}(x- \color{blue}{h})^2 +\color{green}{k}\\y = \color{red}{2}(x- \color{blue}{(-3)})^2 +\color{green}{(-4)}\)