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how did you get that? @Loser66
what does the mean value theorem say?
If f is continuous on a closed interval [a, b], then f attains an absolute maximum value f(c) and an absolute minimum value f(d) at some numbers c and d in [a, b].
What does it mean? |dw:1451852140429:dw|
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there exists a point c on f such that \(f'(c) = \dfrac{f(a) -f(b) }{a-b}\)
|dw:1451852232928:dw|
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