Question

Solve the systems using substitution.

6x + 2y = 0
4x + y = -1

Answer 1

frm equation 2, let
y=-1-4x
now sub that into equation 1

Answer 2

for number 1
Let's solve for x.
6x+2y=0
Step 1: Add -2y to both sides.
6x+2y+−2y=0+−2y
6x=−2y

Answer 3

Step 2: Divide both sides by 6.
6x/6=-2y/6

Answer 4

so u'll get something like -1/3

Answer 5

check to make sure though

Answer 6

In Mathematica, the equations can can be evaluated at x and y equals -1 and 3
respectively. If the LHS and RHS for each equation, post substitution, are equal, then
"True" is returned, else "False". /. is the replacement operator.

{ 6x+2y=0, 4x+y=−1 } /. {x→−1,y→3}

{True, True}