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Given that f(x)=(x-2)(x^3+ax^2+bx+c). Find values of a,b,c.
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Is that the entire problem?
oh, i just realised its given that f(x)=x^4-4x-4x-8
so would you do that one divide by x-2?
well you need to do polynomial or synthetic division to get the coefficients a, b and c
opps the original function is missing some info... powers of x
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no, thats what the question says. I guess i would have to use 0x^3 and 0x^2 to fill in the blanks to divide
you have \[x^4 - 4x - 4x -8 = x^4 - 8x - 8\] so I think there is a power missing
i dunno, thats what it says on the paper?
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