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solve the linear system using substitution. x=y+3 2x-y=5
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x=y+3 <--equation 1 2x-y=5 <---equation 2 x value is given so plug it into equation 2 \[\huge~\rm~\bf~2(y+3)−y=5 \]
Solve for y.
Plug in the first equation into the second equation. Can you tell me what you get? :)
dang the lag :/
|dw:1452045697900:dw| y=-1
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