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solve the linear system using substitution. 2x=12 x-5y=-29
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first divide both sides by 2 in the equation 2x=12
x=6
now, substitute 6 for x in the second equation. (6)-5y=-29
Subtract 6 from both sides: -5y=-35
Divide both sides by -5 y=7
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Plug in 7 for y to get the x x-5(7)=-29 x-35=-29 x=6
y=7 x=6
That was a check, because from the first equation you already know that x=6.
thank you very much
can you help me with one more?
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