Question

What is the range of the function f(x) = 3x2 + 6x – 8

Answer 1

lemme check

Answer 2

Manipulate your equation into the "vertex form":
y= a(x-h)^2+k
where
(h,k) is the vertex
.
f(x) = 3x^2 + 6x - 7
f(x) = (3x^2 + 6x) - 7
f(x) = 3(x^2 + 2x) - 7
Complete the square:
f(x) = 3(x^2 + 2x + 1) - 7 - 3
f(x) = 3(x+1)^2 - 10
.
Therefore, the vertex is:
(h,k) = (-1, -10)
.
To find the y-intercepts, set x=0 and solve for f(x):
f(x) = 3x^2 + 6x - 7
f(x) = 3(0^2) + 6(0) - 7
f(x) = - 7
y-intercept is (0, -7)
.
To find x-intercepts, set f(x)=0 and solve for x:
0 = 3x^2 + 6x - 7

Answer 3

answer at the bottom bruh

Answer 4

ight thanks

Answer 5

You're not supposed to give direct answers @Richie63 . I understand the work and all but you should have just backspaced on the actual answer b/c you can get into trouble for that.. And I already know you got the answer from a website ;)