Question

PLEASE HELP!!
The length (L) of a photograph is 8mm longer than its width (W). Its
perimeter (P) is more than 60mm.
𝐏 = 𝟐𝐖 + 𝟐𝐋
a) Write an equation for the length in terms of the width
L = _____________________
b) Use these expressions to write an inequality based on the given information.
c) Solve the inequality clearly indicating the length and width of the photograph.
d) Write your answer in a complete sentence

Answer 1

@satellite73

Answer 2

@nincompoop

Answer 3

@Rushwr

Answer 4

@ChantySquirrel1129**

Answer 5

What is the inequality

Answer 6

i have no idea what a inequality is :/

Answer 7

my brother help me solve (a) but in still confused about (b) (c) and (d)

Answer 8

Show me your equation

Answer 9

for a?

Answer 10

L = (P - 2W) / 2

Answer 11

The length (L) of a photograph is 8mm longer than its width (W). Its
perimeter (P) is more than 60mm.

Length is 8mm mre than it's width

So L = w + 8

It's perimeter is 60mm or more. \[2(w + 8) + 2w /\ge 60\]

Answer 12

@Compassionate - i think more than 60 mm mean strictly greater than 60 and not can being equal 60 - how you think it ?

Answer 13

L=w+8 would be a?

Answer 14

My logic being, if you take all the sides of a triangle, it will either be equal to or greater than the perimeter. But, hey.

2(w + 8) 2w > 60 will yield the same solution.

Answer 15

pardon - just for ,,asker" understand it sure clearly - ty !!!

Answer 16

@nincompoop how you think than the perimeter need being strictly greater than 60 this mean that the length and width of sides need being strictly greater not smaller - how you have wrote above - check it please

prove than l < 19 --- 2l < 38 and w<11 --- 2w < 22
-----------------------------------------------
perimeter resulte strictly < than 38+22=60

but in the text of exercise have wrote strictly greater

how you think it so ????

Answer 17

width is greater than 11
length is width + 8

Answer 18

let me re-write so it is not confusing.

The length (L) of a photograph is 8mm longer than its width (W). Its
perimeter (P) is more than 60mm.
𝐏 = 𝟐𝐖 + 𝟐𝐋
a) Write an equation for the length in terms of the width
L = _____________________
b) Use these expressions to write an inequality based on the given information.
c) Solve the inequality clearly indicating the length and width of the photograph.
d) Write your answer in a complete sentence

Answer 19

IF
P = 2W + 2L
then,
2W + 2L > 60
is the same way as
P > 60 in words: perimeter is greater than 60

L = W+8 (a) length in terms of width
L-8 = W (*) width

2(W+8) + 2W >60
2W+16 + 2W > 60
4W + 16 > 60
4W > 60 -16
4W > 44
W > 11

W+8 = L
11<W+8 = L

Width is greater than 11
Length is W+8

Answer 20

L=W+8?

Answer 21

more specifically
11<W+8 = L
because there is a restriction in the value of width

Answer 22

the value of length is dependent on the value of width
the value of width is anything greater than 11
so, we can say that the value of length is greater than 19

Answer 23

okay