Question

@mathmale @freckles

Answer 1

Evaluate the integral

Answer 2

@mathmale @freckles @xapproachesinfinity

Answer 3

find the lower bound and upper bound properly first

Answer 4

???

Answer 5

hmm?

Answer 6

fine you want something else to do
use substitution
\(s=\sqrt{u} \) then look for ds

Answer 7

k, I'l try that...

Answer 8

you should also try to make it a habit checking if there's an improper bound

Answer 9

well...basically I already found the antiderivative of \(\large 1-\sqrt{u}\) and \(\large \frac{1}{\sqrt{u}\) but I don't know how to combine them

Answer 10

\(\large\frac{1}{\sqrt{u}}\)

Answer 11

hmm

Answer 12

make sure

Answer 13

\(\huge \sqrt{u} = u^{\frac{1}{2}} \)

Answer 14

try again