Question

HELP ASAP ONE PRE_ALGEBRA QUESTION PLEASE:

Answer 1

@jim_thompson5910 ?

Answer 2

(x^2 + 8x + 4) / (x^2 - x - 6)

Factor the bottom.
(x^2 + 8x + 4) / ( (x - 3) (x + 2) )

Set the bottom equal to zero.
x - 3 = 0 x = 3
x + 2 = 0 x = -2

Confirm the x values do not cause the top to be zero (it would then be a hole, still a discontinuity, but not a asymptote).
(-2)^2 + 8 (-2) + 4 = -8
(3)^2 + 8(3) + 4 = 37

Neither do so x = -2, 3 are both vertical asymptotes, aka discontinuities.
Will ·

Answer 3

u got it

Answer 4

so i did do it right?

Answer 5

@Prettygirl_shynice

Answer 6

yea im here

Answer 7

Did i get the right answer then?

Answer 8

do u think u did

Answer 9

yes

Answer 10

well yea then

Answer 11

i came for a confirmation though

Answer 12

i understnad what you saying but yea u did

Answer 13

good job

Answer 14

thank you so much!:_)

Answer 15

@iwanttogotostanford ur welcome

Answer 16

u need help with anymore