Ask your own question, for FREE!
Mathematics 21 Online
OpenStudy (alexh107):

Rewrite with only sin x and cos x. sin 3x - cos x

OpenStudy (alexh107):

These are the choices.

OpenStudy (trojanpoem):

sin3x = sin(x+2x) = sinxcos2x + cosx sin2x sinx (cos^2x- sin^2x) + cosx * 2 sinx cosx sinxcos^2x - sin^3x + 2sinxcos^2x 3sinxcos^2x - sin^3x - cosx

OpenStudy (trojanpoem):

so it's B

OpenStudy (alexh107):

Oh I see, I was getting confused because the answers looked different but now I realize they are the same.

OpenStudy (trojanpoem):

2sinxcos^2x + sinx(1-2sin^2x) - cosx 2sinxcos^2x + sinx cos2x - cosx 2sinxcos^2x + (cos^2x - sin^2x) sinx - cosx 2sinxcos^2x + sinxcos^2x - sin^3x - cosx 3sinxcos^2x - sin^3x - cosx

OpenStudy (alexh107):

Thank you!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!