Question

If (f + g)(x) = 3x^2 + 2x – 1 and g(x) = 2x – 2, what is f(x)?

Answer 1

@mathmale

Answer 2

he's not coming

Answer 3

Fair enough he is probably busy

Answer 4

Can you help?

Answer 5

Nope im not good at that

Answer 6

3x2 + 1
3x2 – 1
3x2 + 4
3x2 – 4
x2 – 2

Answer 7

okay thats anyway

Answer 8

but i'll try

Answer 9

Oh good :)

Answer 10

nvm ik the answer

Answer 11

a) g^-1(x), the inverse of g(x)
Let’s follow a few steps for inverse functions:
Put y for the g(x) expression,
Switch x for y
Solve for y as the inverse function

Thus y = 2x + 2
Switching x for y,
X = 2y + 2
2y = x – 2
Y = (x-2)/2
So g^-1(x) = (x-2)/2

Answer 12

im 100% sure

Answer 13

It doesnt match an answer choice lol but good try

Answer 14

b) (fog^-1)(2) means substituting g inverse (g^-1) into f(x) when X = 2
Thus, fog^-1(x); x = 2
fog^-1(x) = 3((x-2)/2)^2) + 1
when x = 2
fog^-1(2) = 3((2-2)/2)^2) + 1
= 0 +1
= 1

Answer 15

is one a answer choice

Answer 16

#1

Answer 17

I posted the answer choices

Answer 18

3x2 – 1

Answer 19

Okay thanks

Answer 20

if it's wrong tell me :)))))

Answer 21

I will