WILL MEDAL

Seth is using the figure shown below to prove Pythagorean Theorem using triangle similarity:

In the given triangle ABC, angle A is 90o and segment AD is perpendicular to segment BC.

Which of these could be a step to prove that BC2 = AB2 + AC2?

Question

WILL MEDAL

Seth is using the figure shown below to prove Pythagorean Theorem using triangle similarity:

In the given triangle ABC, angle A is 90o and segment AD is perpendicular to segment BC.

Which of these could be a step to prove that BC2 = AB2 + AC2?

anonymous · Answer

https://njvs.desire2learn.com/content/enforced/15358-CO_4636/0507ModuleFiveExamPartOne/image0014e8ca85a.gif?_&d2lSessionVal=O5ppnu1yJRh3f7PcLtBeK2YDB

anonymous · Answer

@Decarr432

anonymous · Answer

1) 	By the cross product property, AB2 = BC multiplied by BD.
	
2) 	By the cross product property, AC2 = BC multiplied by BD.
	
3) 	By the cross product property, AC2 = BC multiplied by AD.
	
4) 	By the cross product property, AB2 = BC multiplied by AD.

anonymous · Answer

I think that it is either 3 or 4

decarr432 · Answer

I'm fairly certain its 3 but ask @mathmale he knows best

anonymous · Answer

Ok thanks!

anonymous · Answer

@mathmale can you double check this please?